Hello friends, Welcome to your **Techgsr.co** blog. And today in this article we will learn about **how to create Program to convert 2-digit octal number into binary number and print it** .So let’s go to our topic

#include <iostream.h> #include <conio.h> void octobin(int); void main() { clrscr(); int a; cout << “Enter a 2-digit octal number : “; cin>>a; octobin(a); getch(); } void octobin(int oct) { long bnum=0; int A[6]; //Each octal digit is converted into 3 bits, 2 octal digits = 6 bits. int a1,a2,quo,rem; a2=oct/10; a1=oct-a2*10; for(int x=0;x<6;x++) { A[x]=0; } //Storing the remainders of the one’s octal digit in the array. for (x=0;x<3;x++){ quo=a1/2; rem=a1%2; A[x]=rem; a1=quo; } //Storing the remainders of the ten’s octal digit in the array. for(x=3;x<6;x++) { quo=a2/2; rem=a2%2; A[x]=rem; a2=quo; } //Obtaining the binary number from the remainders. for(x=x-1;x>=0;x—) { bnum*=10; bnum+=A[x]; } cout << “The binary number for the octal number ” << oct << ” is ” << bnum << “.” << endl; }

This program takes in a two-digit octal number a as a screen input from the user.

It then converts the octal number into a binary number and outputs it using the ‘cout’

command.

INPUT :

13

OUTPUT :The binary number for the octal number 13 is 1011.

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